Tag Archives: NF

OFS does not apply to few records in awk

April 28, 2013 Bartle Doo Leave a comment

Hi ,

I am having a problem with my awk oneliner , which for some reason leaves the first two records

Input File

Code:

$ cat file1

A1:B1:C1:NoLimit

M1:M2:M3:Limit

A2:B2:C2,C3,C4,C5

A3:B3:C3,C4,C5,C6,C7

Desired output

Code:

A1,B1,C1,NoLimit

M1,M2,M3,Limit

A2,B2,C2

,,,C3

,,,C4

,,,C5

A3,B3,C3

,,,C4

,,,C5

,,,C6

,,,C7

I am using the below oneliner to achieve it partially but i dont get why the first two records OFS does not change to comma
,

Code:

nawk 'BEGIN{FS=":";OFS=","}{gsub(",","n,,,",$NF);print}' file1

This gives me an output

Code:

A1:B1:C1:NoLimit

M1:M2:M3:Limit

A2,B2,C2

,,,C3

,,,C4

,,,C5

A3,B3,C3

,,,C4

,,,C5

,,,C6

,,,C7

Can someone please help me understand the problem and correct the code

Source: FULL ARTICLE at The UNIX and Linux Forums

Linux

Case script to get missing sequence among files

April 28, 2013 Bartle Doo Leave a comment

By arm

I want to use case statement to find the range of missing sequence in my directory which it has some few ( dat & DAT ) files

my directory /home/arm/my_folder/20130428 contains :

f01_201304280000.DAT
f01_201304280001.DAT
f01_201304280003.DAT
f02_201304280000.dat
f02_201304280002.dat
f02_201304280003.dat

Code:

!#/bin/sh

main="/home/arm/my_folder"
for file in $( find $main -type f | awk -F "/" '{ print $NF}' | cut -c1-3 )

do
case $file in

f01) start=$( find $main -type f -name "$file*" | sort | cut -c13-16 | head -1)

     end=$( find $main -type f -name "$file*" | sort | cut -c13-16 | tail -1 )

     diff=$(( $end - $start ))

     miss=$file*diff*

     echo $miss
f02) start=$( find $main -type f -name "$file*" | sort | cut -c13-16 | head -1)

     end=$( find $main -type f -name "$file*" | sort | cut -c13-16 | tail -1 )

     diff=$(( $end - $start ))

     miss=$file*diff*

     echo $miss

esac

done

hope you can correct me if I were wrong ?

Source: FULL ARTICLE at The UNIX and Linux Forums

Linux

Please help to fix awk script

April 17, 2013 Bartle Doo Leave a comment

By snysmumrik

Good morning, fellows. I would need to ask for your help in editing my awk script. Here is the original version:

BEGIN { printf (“CRYST1 200.000 200.000 200.000 90.00 90.00 90.00 P 1 1n”)
maxatoms=1000
natom=0
found_struct = 0
found_bond = 0
}
{
if( NF == 5 )
{
foundff=0
natom++
fftype[natom]=”UNKNOWN”
if ($1 ~ /CT/)
{
fftype[natom] = “C”
foundff=1
}
else if ($1 ~ /OH/)
{
fftype[natom] = “O”
foundff=1
}
else if ($1 ~ /HC/)
{
fftype[natom] = “H”
foundff=1
}
else if ($1 ~ /N/)
{
fftype[natom] = “N”
foundff=1
}

else if ($1 ~ /H1/)
{
fftype[natom] = “H”
foundff=1
}
else if ($1 ~ /HO/)
{
fftype[natom] = “H”
foundff=1
}
else if ($1 = “C”)
{
fftype[natom] = “C”
foundff=1
}
else if ($1 = “O”)
{
fftype[natom] = “O”
foundff=1
}

x[natom] = $1
y[natom] = $2
z[natom] = $3

if (foundff == 0)
printf(“PROBLEM : Atom ff type %s not knownn”, $6)
}

}

END {
for (iatom=1; iatom <= natom; iatom++)
{
printf(“HETATM %d %2s %d %14.9f %14.9f %14.9fn” ,
iatom, fftype[iatom], iatom, x[iatom], y[iatom], z[iatom])
}
printf (“ENDn”)
}

And this is type of file I am working with.

0 3 186 200 75202
timestep 500 186 0 3 0.002000 1.000000
40.0000000000 0.0000000000 0.0000000000
-0.0000000034 40.0000000000 0.0000000000
-0.0000000034 -0.0000000034 40.0000000000
CT_1 1 12.011000 0.061000 1.087513
-1.961325738 1.828501682 -8.933652557
CT_1 2 12.011000 0.061000 0.789711
-3.851025437 3.495427316 -10.05849230
CT_1 3 12.011000 0.061000 0.581330
-5.804493575 4.589489777 -8.369482861

ect

I would like to get this as an output:

CRYST1 200.000 200.000 200.000 90.00 90.00 90.00 P 1 1
HETATM 1 C 1 -1.961325738 1.828501682 -8.933652557
HETATM 2 C 2 -3.851025437 3.495427316 -10.05849230
HETATM 3 C 3 -5.804493575 4.589489777 -8.369482861

ect

But coordinates are not really picking up well (next line after CT_1 1 12.011000 0.061000 1.087513). Can you please have a look and suggest any solutions. Thanks.

From: http://www.unix.com/unix-dummies-questions-answers/221317-please-help-fix-awk-script.html

Business, Finance, Occupation & Industry

Synta Announces Presentations at the 2013 Annual Meeting of the American Association of Cancer Resea

April 5, 2013 Bartle Doo Leave a comment

By Business Wirevia The Motley Fool

Filed under: Investing

Synta Announces Presentations at the 2013 Annual Meeting of the American Association of Cancer Research

LEXINGTON, Mass.–(BUSINESS WIRE)– Synta Pharmaceuticals Corp. (NAS: SNTA) announced today that poster presentations related to studies with ganetespib, a selective Hsp90 inhibitor in clinical development by the company, will be presented at the 2013 Annual Meeting of the American Association of Cancer Research in Washington, D.C. Presentations include:

Inhibition of mTOR enhances the activity of HSP90 inhibitors in part through cessation of heat shock protein synthesis

Presentation: Sunday, April 7, 1:00 – 5:00 PM ET
Abstract number: 1038
Authors: He, et al.

Ultra-deep sequencing of circulating free DNA to identify predictive, mutated HSP90 clients in the GALAXY Trial (NCT01348126): a randomized phase IIB/III study of ganetespib (STA-9090) in combination with docetaxel versus docetaxel alone in subjects with stage IIIb/IV NSCLC

Presentation: Monday, April 8, 1:00 – 5:00 PM ET
Abstract number: 2012
Authors: Fennell, et al.

The importance of dose schedule with HSP90 inhibitors: Results from a Phase II study in dogs with mast cell tumors

Presentation: Tuesday, April 9, 8:00 AM – 12:00 PM ET
Abstract number: 3369
Authors: London, et al.

Differential sensitivities to heat shock protein 90 (HSP90) inhibitors in anaplastic lymphoma kinase (ALK)-positive non-small cell lung cancer (NSCLC) cells

Presentation: Tuesday, April 9, 8:00 AM – 12:00 PM ET
Abstract number: 3272
Authors: Lee, et al.

Heat shock protein 90 functional inhibition regulates epithelial to mesenchymal transformation, invasion and migration via NF-kB and HIF-1α signaling in colorectal cancer

Presentation: Tuesday, April 9, 8:00 AM – 12:00 PM ET
Abstract number: 2707
Authors: Ganji, et al.

About Ganetespib

Ganetespib is an inhibitor of heat shock protein 90 (Hsp90) that is structurally unrelated to first-generation, ansamycin-related Hsp90 inhibitors. In preclinical experiments, ganetespib has shown activity in multiple tumor models …read more

Source: FULL ARTICLE at DailyFinance

Linux

Adding a specified value to a specified column – awk?

April 4, 2013 Bartle Doo Leave a comment

By radudownload

Hi everyone!

I sometimes need to do some simple arithmetics, like adding a number to a certain column of a file. So I wrote a small function in the .bashrc file, which looks like this

Code:

 shifter()

 {

 COL=$1

 VAL=$2

 FILE=$3

cp $FILE $FILE.shifted awk 'NF==4 {$(( $COL )) = $(( $COL )) + $VAL}' $FILE.shifted }

which should add the number stored in VAL, to the column COL from the FILE file.

Please give me a hint how should I make this work. Thank you! (I’m just a newbie in shell programing)

Linux

Search for a word and print the next word

April 4, 2013 Bartle Doo Leave a comment

By sampoorna

Hi,

I am trying to search for a word and print the next word. For example:

My text is “”

I am searching for “TYPE” and trying to print =”Lookup Procedure”

I have written a code like following:

Code:

echo $line | nawk '{for(i=1;i<NF;i++){if($i~/^TYPE/){print $(i+1)}}}'

But the output is coming as “Lookup

Please help, thanks

Linux

Print a newline after first match in line

April 4, 2013 Bartle Doo Leave a comment

By meet77

Hi everyone
I have a file where CP occurs both within each line and at the very end:

dwer 17 knsdask= * CP hwla 17 h’wopie un CP

I would like to separate the line on the first CP to get:

dwer 17 knsdask= * CP
hwla 17 h’wopie un CP

What I have so far is:
awk ‘{for (x=1; x<NF; x++)
{if ($x~/CP/)
{printf “%sn”} }}’ file

Reagrds

Linux

System function in awk

April 2, 2013 Bartle Doo Leave a comment

By EAGL€

Hello Friends,

I have written a script like below,

I aimed to move some CDR files (call data record) whose the last field is “1” (NF=1 ) from a spesific directory to a new directory
Field Seperator is pipe.
If the directory does not exitst i should create it.
I will give the script two arguments so i check if they are given or not

Here I have written this; Im suspicious if the below system function in awk will work or not, appreciate your opinions.

Code:

if [ "$#" -ne 2 ]

then

        echo 

        echo "--- There are two arguments which is expected after script! ---"

        echo "--- USAGE: "$0" | FULL PATH of NEPS DIRECTORY | NEW FULL PATH for INITIALLY CHARGED CDRs ---"

        echo

elif [ "$#" -eq 2 ]

then

        if [ ! -d $2 ];

        then

                mkdir $2

        fi

for file in `find $1 -type f -name "*cdr*.txt" 2>/dev/null` do nawk -F| -v PATH=$2 'NR==1{ if $NF==1 system( "mv FILENAME PATH/FILENAME ") }' done; fi

Thanks in advance
BR

Linux

How to deal with multidimensional array in awk?

March 27, 2013 Bartle Doo Leave a comment

By Akshay Hegde

Hi all!

I would like to know how to print

Code:

$0

when using multidimensional array like below

time being I am using for loop to print columns like this

Code:

awk 'FNR==1{i++}

{for(k=1;k<=NF;k++)A[i,FNR,k]=$k}

END{for(j=1;j<=25;j++)

print A[2,1,1],A[2,1,2],A[2,j,3],A[2,j,4],A[2,j,1],A[2,j,2],A[2,j,3],A[2,j,4],A[1,j,1],A[1,j,1],A[1,j,2],A[1,j,3],A[1,j,4],A[1,j,1]}' file1 file2

so here my problem is I have more than 15 column that means whether I have to type like below till 15th column

Code:

A[2,j,1],A[2,j,2],.....A[2,j,15]

or any other solution is available ?

thanks in advance

Linux

Help me for using the awk command in UNIX

March 22, 2013 Bartle Doo Leave a comment

By avig

Hi,

Can you please help me to find/display out last Friday’s date of the month using awk command in Unix/Linux.

i have found this command

cal 03 2013 | awk ‘NF>5{last = $6} END{print last}’

it show the output in single digit date like :29

But i need its output will shown in Fri Mar 29 2013

Please help.

Linux

What is wrong with this awk statement?

March 20, 2013 Bartle Doo Leave a comment

By SkySmart

Code:

echo $line | awk -F, "BEGIN {if(NF==10) && /'"${MONTH}"' '"${DAY}"' '"${TIMEH}:"'/,0 {print $10"-"$4} else {print $13"-"$4}}"

if the fields in the line is equal to 10, print the values of this specified fields “$10 and $4”.

if the fields in the line is anything but 10, print the values of field “$13 and $4”.

Linux

Print column header

March 20, 2013 Bartle Doo Leave a comment

By kedar_laveti

Hi,

Below is the data in a tab limited file

Quote:

ACCENT

Pcode Dealer Name Comp INF

Here ACCENT is just a heading and the line starting with Pcode has the column headers, and there is a 2 lines space between the file header and column header.

I want to print $2, that is Dealer Name

I used the below code

Code:

nawk 'NF>1{print $2; exit}' File.txt

But the result is coming only Dealer, whereas the result should be Dealer Name, what should be done to get the result as Dealer Name.

Please help.

Thanks

Linux

How to take awk result out (piping to other program)?

March 19, 2013 Bartle Doo Leave a comment

By Akshay Hegde

Hi! all here is my code
which is working fine no errors but I want to know how to take result and input to other program

Code:

awk 'FNR==1{i++}{LC[i]=NR} 

{for(k=1; k<=NF; k++) A[i,FNR,k]=$k}                                 

END{for (i=1;i<=LC[1];i++)

{

for(j=1;j<=LC[2];j++)

if(A[2,j,8]=='$UID' && A[2,j,4]>='$MX'+A[1,i,3] && A[2,j,4]<='$MIN'+A[1,i,4] && 

A[2,j,4]>='$MN'+A[1,i,1] && A[2,j,5]<='$MX'+A[1,i,2])

print A[2,j,6],A[2,j,7]

}}' OFS="t" STD_FIILE FILE2 | program(print) command -XA[2,j,5] -Y[2,j,5]   -------------> if statement is true

if if statement is awk program in false

then

Code:

OFS="t" STD_FIILE FILE2 | program(mask) command -XA[2,j,5] -Y[2,j,5] ------------->

please help me

Linux

awk processing of passed variables

March 18, 2013 Bartle Doo Leave a comment

By Mid Ocean

Currently have this:

Code:

set current=192.168.0.5

set servicehost = `echo $current | awk -F. '{print $4}'`

echo $numberoffields

..but would like to reduce # of variables and eliminate echo to have something like this:

Code:

set servicehost = `awk -v s="$current" -F. 'BEGIN{print $2}'`

But doesn’t work. In a similar vein how to determine NR and NF on variables passed via -v .. if possible. For example how to replace the following:

Code:

set string = "hello world"

set numberoffields = `echo $string | awk '{printf("%sn",NF)}'`

echo $numberoffields

..with something like this:

Code:

set string = "hello world"

set numberoffields = awk -v s=$string 'BEGIN{printf("%sn",NF)}'

echo $numberoffields

Would be great if it returned 2 somehow 🙂

Linux

'AND' boolean not working !!!!

March 17, 2013 Bartle Doo Leave a comment

By emily

Dear all,
IT seems to be rather small issue, but is not resolved. What Google suggest does no work..!

Code:

#!/bin/bash                                                                                                                                           

date
jobNo=$(awk '/Jobs with Wrapper/ && $NF != 0{s=1}   /List of jobs/ && s{if(p){p=p","$NF}else{p=$NF};s=""}END{print p}' test.log )

jobNo1=$(awk '/List of jobs Cancelled/ && $NF != 0{s=1} s{if(p){p=p","$NF}else{p=$NF};s=""}END{print p}'  test.log)
      #if No JobNo                                                                                                                                    

if [ "$jobNo" = "" ]; then

    echo "Resubmitting" $jobNo1 "=============-----------------------------------------------"

    echo "crab ntuplize_crab -resubmit" $jobNo1 "-c"

#if No JobNo ...read more Source: FULL ARTICLE at The UNIX and Linux Forums

Linux

Issues in reading file using 'awk'

March 16, 2013 Bartle Doo Leave a comment

By emily

Dear all,
I am using following function of some script to assign variable “JobNo” some value form file $SAMPLE”_status.log” [1] ( generated using the red color command )

Code:

  

   crab ntuplize_crab -status -c $SAMPLE >& $SAMPLE"_status.log" &  

   echo $SAMPLE"_status.log" "====="  

   jobNo=$(awk '/Jobs with Wrapper/ && $NF != 0{s=1}   /List of jobs/ && s{if(p){p=p","$NF}else{p=$NF};s=""}END{print p}' $SAMPLE"_status.log" )

    #sleep 200

echo $jobNo "=====" echo $jobNo "====="

The name of the file is correctly printed on the screen and also I checked the content is fine which is [1].
Now, the execution of this script pass me the following output:

Code:

 

qcd120_status.log =====

=====

=====

The blue is the file name and is fine. But when I am trying to print the JobNo it only print the “====”..
And when I use the above command on the terminal it is passing me the proper JobNo which I want, should be following:

Code:

 57,331,333,336,348,2-3,11,28,45,49,67-68,80,82,87,102-104,107-108,111-112,114,117-118,123-125,127-132,134,139,148-157,159-161,169-172,174,179-180,182-185,200,202,204,208-210,219,226,236,238,245,251,253-257,262,265,271,280,288,308,330,353,355,375,377,381,385,387

Please help, I am completely stuck.

[1]

Code:

 crab:  ExitCodes Summary

 >>>>>>>>> 309 Jobs with Wrapper Exit Code : 0

         List of jobs: 1,4-10,12-27,29-44,46-48,50-56,58-66,69-79,81,83-86,88-101,105-106,109-110,113,115-116,119-122,126,133,135-138,140-147,158,162

-168,173,175-178,181,186-199,201,203,205-207,211-218,220-225,227-235,237,239-244,246-250,252,258-261,263-264,266-270,272-279,281-287,289-307,309-329,

332,334-335,337-347,349-352,354,356-374,376,378-380,382-384,386,388-401

        See https://twiki.cern.ch/twiki/bin/view/CMS/JobExitCodes for Exit Code meaning
crab:  ExitCodes Summary

 >>>>>>>>> 4 Jobs with Wrapper Exit Code : 8028

         List of jobs: 57,331,333,336

        See https://twiki.cern.ch/twiki/bin/view/CMS/JobExitCodes for Exit Code meaning
crab:  ExitCodes Summary

 >>>>>>>>> 1 Jobs with Wrapper Exit Code : 8021

         List of jobs: 348

        See https://twiki.cern.ch/twiki/bin/view/CMS/JobExitCodes for Exit Code meaning

crab: ExitCodes Summary >>>>>>>>> 87 Jobs with Wrapper Exit Code : 60307 ...read more Source: FULL ARTICLE at The UNIX and Linux Forums

Linux

Print column postion

March 15, 2013 Bartle Doo Leave a comment

By sampoorna

Hi,

I am using the below code for printing the column position of a particular string

Quote:

nawk -v srch=”DName” -F ‘t’ ‘{for(j=1; j<=NF; j++) { if($j==srch) print j } exit }' input_file.txt

The above code prints the column position of the input string DName (that is 1)

Now the problem is, the above code is working fine for the data that starts from 1st line in a tab delimited file, but it is not working for files where the data is starting from 2 or 3 rd row.

Can anybody plz help.

Thanks

Linux

CSV to CSV MS-DOS

March 14, 2013 Bartle Doo Leave a comment

By shadyuk

Hello,

I have the following script which converts some data in a CSV file from one format to another. However, I have to convert the CSV (Macintosh) file to CSV or CSV (MS-DOS) first else the script wont work. I do this in Excel. I know it has something to do with the line endings, where CSV (Macintosh) saves with CR as the new-line character, and CSV (Comma delimited) and CSV (DOS) both use CR/LF.

Is there a way to add something to the top of my script that negates the need for me to convert manually?

Code:

#!/bin/ksh

if [ $# -ne 1 ] || [ ! -f "$1" ] then echo "Usage: $0 file" >&2 exit 1 fi awk ' NR==1{ $0="header1,header2,headerN" } NR>1{ for(i=2; i<=NF; i++) if($i~/^[KMG0-9]+/[KMG0-9]+$/) sub("/",",",$i) $0=$0 for(i=2; i<=NF; i++) if($i~/^[KMG0-9]+$/){ p=0 if($i~/G/) p=9 if($i~/M/) p=6 if($i~/K/) p=3 sub(/[GMK]/,".",$i) $i*=10^p } } 1 ' FS=, OFS=, "$1"

Linux

Why result is wrong here ? whether break statement is wrong ?

March 10, 2013 Bartle Doo Leave a comment

By Akshay Hegde

Hi ! all I am just trying to check range in my datafile

pls tell me why its resulting wrong

Code:

admin@IEEE:~/Desktop$ cat test.txt

0    28.4

5    28.4

10    28.4

15    28.5

20    28.5

25    28.6

30    28.6

35    28.7

40    28.7

45    28.7

50    28.8

55    28.8

60    28.8

65    28.1

70    26.5

This I tried

Code:

awk 'FNR==1{i++}{LC[i]=NR} 

{for(k=1; k<=NF; k++)A[i,FNR,k]=$k}     #ARRAY                           

END{

j=1;

while(j<=LC[1])                # IF J<=Line Count do following

{

x=A[1,j,2]-A[1,1,2]            # Column2 records - Column2 1st Record

if(x>0.1)                # IF above statement result is greater than 0.1

break;                    # Break loop, save index in variable,save column2 record

p1=j;

h1=A[1,j,1];                # IF not increment j

j++;

}

l=1; while(l<=LC[1]) # IF l<=Line Count do following { y=A[1,l,2]-A[1,1,2] # Column2 records - Column2 1st Record if(y<-0.1) # IF above statement result is less than 0.1 break; # Break loop, save index in variable,save column2 record p2=l; h2=A[1,l,1]; # IF not increment l l++; } { for(m=p1;m<=p2;m++) # Use Index stored in p1 and p2 of 1st and 2nd while loop print records in that range {print A[1,m,1],A[1,m,2],h1,h2,p1,p2,FILENAME,x,y,A[1,1,2],A[1,1,1]} } }' OFS="t" test.txt

Resulting

Code:

admin@IEEE:~/Desktop$ sh awk.sh 

10    28.4    10    60    3    13    test.txt    0.1    -0.3    28.4    0  --This is wrong

15    28.5    10   ...read more 
Source: FULL ARTICLE at The UNIX and Linux Forums

Linux

URL extraction from JSON file

March 6, 2013 Bartle Doo Leave a comment

By busyboy

I’m trying to export URLs from within a JSON file which in turn resulted from export of Mozilla-Firefox bookmarks. Its single line file with below given values from awk

Code:

$ awk 'END { print NR }' bookmarks.json

1

$ awk 'END { print NF }' bookmarks.json

2706

$ awk -F, 'END { print NF }' bookmarks.json

4754

using sed, it gives me only 1st occurrence and rest is missed.

Code:

$ sed  's/.*"(http:.*)"/1/' bookmarks.json

http://www.oracle.com/us/products/servers-storage/servers/blades/index.html","charset":"UTF-8}]}]}

$

extract from json file is something like below:

Code:

{"title":"","id":1,"dateAdded":1331548812311000,"lastModified":1331549028262000,"type":"text/x-moz-place-container","root":"placesRoot","children":[{"title":

"Bookmarks Menu","id":2,"parent":1,"dateAdded":1331548812311000,"lastModified":1342096853234000,"type":"text/x-moz-place-container","root":"bookmarksMenuFold

er","children":[{"title":"Recent Tags","id":925,"parent":2,"annos":[{"name":"Places/SmartBookmark","flags":0,"expires":4,"mimeType":null,"type":3,"value":"Re

centTags"}],"type":"text/x-moz-place","uri":"place:sort=14&type=6&maxResults=10&queryType=1"},{"index":1,"title":"Recently Bookmarked","id":924,"parent":2,"a

nnos":[{"name":"Places/SmartBookmark","flags":0,"expires":4,"mimeType":null,"type":3,"value":"RecentlyBookmarked"}],"type":"text/x-moz-place","uri":"place:fo

lder=BOOKMARKS_MENU&folder=UNFILED_BOOKMARKS&folder=TOOLBAR&sort=12&excludeQueries=1&maxResults=10&queryType=1"},{"index":2,"title":"","id":26,"parent":2,"da

teAdded":1243009025055489,"lastModified":1331549044829000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{445

36f3f-1d99-4e6d-8b77-d5e89c334d2d}2"}],"type":"text/x-moz-place-separator"},{"index":3,"title":"Get Bookmark Add-ons","id":27,"parent":2,"dateAdded":12430090

25055489,"lastModified":1331549044829000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{44536f3f-1d99-4e6d-8

b77-d5e89c334d2d}3"}],"type":"text/x-moz-place","uri":"https://en-us.add-ons.mozilla.com/en-US/firefox/bookmarks/"},{"index":4,"title":"","id":28,"parent":2,

"dateAdded":1243009025055489,"lastModified":1331549044829000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{

44536f3f-1d99-4e6d-8b77-d5e89c334d2d}4"}],"type":"text/x-moz-place-separator"},{"index":5,"title":"Mozilla Firefox","id":29,"parent":2,"dateAdded":1243009025

055489,"lastModified":1331549044845000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{44536f3f-1d99-4e6d-8b7

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ied":1331549044845000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{44536f3f-1d99-4e6d-8b77-d5e89c334d2d}6"

}],"type":"text/x-moz-place","uri":"http://en-us.www.mozilla.com/en-US/firefox/help/"},{"index":1,"title":"Customize Firefox","id":31,"parent":29,"dateAdded"

:1243009025055489,"lastModified":1331549044845000,"annos":[{"name":"placesInternal/GUID","flags":0,"expires":4,"mimeType":null,"type":3,"value":"{44536f3f-1d

99-4e6d-8b77-d5e89c334d2d}7"}],"type":"text/x-moz-place","uri":"http://en-us.www.mozilla.com/en-US/firefox/customize/"},

Regards,

Bartle Doo Article Archives

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